.includes with array in Javascript

Question

i wonder is there any way to check if in a string there are characters that match the characters in array?

const array = ["cake","hello","ok"];
const string = "hello"
let result = string.includes(array)
console.log(result)
// >false

Nikola Pavicevic · Accepted Answer · 2021-12-26 13:21:29Z

2

Try to switch array and string:

const array = ["cake","hello","ok"];
const string = "hello"
let result = array.includes(string)
console.log(result)

answered Dec 26, 2021 at 13:21

Nikola Pavicevic

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3 Comments

maybe worth to mention, includes is implemented for array and string ...

And the output will be true not false.

if the string change to "helloaeeahwbdhbd", how can i find it?

pilchard · Accepted Answer · 2021-12-26 13:41:10Z

1

I think you're looking for Array#some(): loop through the array and check if any of the elements match the predicate.

Here checking if string includes as a substring any of the strings in array.

const array = ["cake","hello","ok"];
const string = "helloaeeahwbdhbd"
let result = array.some(s => string.includes(s))
console.log(result)

answered Dec 26, 2021 at 13:36

pilchard

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