How do I pass arguments when launching bash script so that specific lines are executed within the script
For example (createfile.sh):
#!/bin/bash
export CLIENT1_DIR="<path1>"
export CLIENT2_DIR="<path2>"
chef-solo -c solo.rb -j client1.json
chef-solo -c solo.rb -j client2.json
Then
$ ./createfile.sh client1
should only execute client1 specific lines, and replacing it with client2 should execute only client2 specific lines.
There are many solutions to this. Here's one:
#!/bin/bash
client="$1"
case "$client" in
"client1") export CLIENT1_DIR="<path1>" ;;
"client2") export CLIENT2_DIR="<path2>" ;;
*) printf 'Invalid client argument: %s\n' "$client" >&2
exit 1 ;;
esac
chef-solo -c solo.rb -j "$client".json
The client variable gets the value of the first command line argument.
The case statement sets either CLIENT1_DIR or CLIENT2_DIR depending on this value (or exits with an error message if an invalid value was used).
Then chef-solo is invoked with the JSON file corresponding to what was given on the command line.
You have the lines in a function:
#!/bin/bash
clientOne(){
## client1 specific lines
echo "one"
}
clientTwo(){
## client2 specific lines
echo "two"
}
case "$1" in
"client1")
clientOne
;;
"client2")
clientTwo
;;
*)
echo "Wrong option" >&2
;;
esac
## Common lines
echo foo
