5
\$\begingroup\$

I have the following Matlab function:

function [res] = a3_funct(x)
    res = 0;
    for i = 1:size(x,1)
        res = res + abs(x(i))^(i+1);
    end
end

It's emulating this equation:

\$f(x) = \sum_{i=1}^{n}|x_i|^{i+1}\$

Here is an example use:

>> a3_funct([1,2,3]')

ans =

    90

I know I should be able to use the sum() function to make this faster, but how do I get the exponents in there?

\$\endgroup\$
0

1 Answer 1

7
\$\begingroup\$

Vectorized approach:

res = sum(abs(x(:).'.^(2:numel(x)+1)))

Read more about vectorization techniques here.

Thus, your function would look like this:

function res = a3_funct(x)
    res = sum(abs(x(:).'.^(2:numel(x)+1)));
return
\$\endgroup\$
0

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.