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Questions tagged [banach-spaces]

A Banach space is a complete normed vector space: A vector space equipped with a norm such that every Cauchy sequence converges.

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0 answers
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Let $I=[0,1]$, $E$ be a banach space and $f:I \rightarrow E$ be a map. Suppose that for every continuous functional $\varphi\in E^*$, the map $\varphi(f):I\rightarrow \mathbb{R}$ is riemann integrable....
Cezar's user avatar
  • 157
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0 answers
33 views

It is evident that if $\ell^1(\mathbb{Z})$ is finitely represented in $X$, then $X$ has the finite tree property. Indeed, $e_1,...,e_{2^n}$ in $\ell^1(\mathbb{Z})$ forms the $(n,2)$ part of a tree in $...
Tucker_The_Cat's user avatar
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Recently, when I studied the spectrum of an operator, I came across two definitions of the resolvent set. In Kreyszig’s book, the definition is as follows: Let $X \ne {0}$ be a complex normed space ...
ëlêtro's user avatar
  • 219
1 vote
1 answer
73 views

Consider the real Banach space $\ell_1(\mathbb{N})$, further denoted just $\ell_1$, consisting of all functions $x: \mathbb{N}\to\mathbb{R}$ such that $\|x\|:=\sum_{n=1}^\infty |x(n)|<\infty$, ...
user446046's user avatar
5 votes
0 answers
41 views

I am looking for references (textbooks or articles) where it is shown that the Banach space $\ell^1$ has the Kadec–Klee property, i.e. that the weak topology and the norm topology coincide on the unit ...
Zlyp's user avatar
  • 658
0 votes
1 answer
96 views

Let $H$ a Hilbert space and $T \in L(H)$ a linear self-adjoint operator, I cannot find the theorem on the internet that tells me that $\ker(T)^{\bot} = \overline{\operatorname{Ran}(T^*)}$. I just want ...
Pietro Schiavone's user avatar
1 vote
0 answers
98 views

Let $X$ and $Y$ be Banach spaces. Let $U$ be an open subset of $X$ and $f:A\rightarrow Y$ be a function with $U\subseteq A\subseteq\overline{U}$. Then we have two possible definitions of $f\in C^{1}(A,...
Karthik Kannan's user avatar
1 vote
1 answer
105 views

On $BV[0,1]$ we can introduce the following norm: $$\lVert f \rVert_{BV} := \lVert f \rVert_{\infty} + V(f)$$ [Here, $V$ is the total variation.] I want to show that this normed space is a Banach ...
user665110's user avatar
7 votes
1 answer
108 views

The Milman-Pettis theorem says that every uniformly convex Banach space is reflexive. I’ve read and understood the proof, but I’m struggling with the motivation. The statement feels mysterious: ...
Tintin's user avatar
  • 917
1 vote
2 answers
210 views

I am trying to understand an argument by Lindestrauss in his paper LIPSCHITZ IMAGE OF A MEASURE-NULL SET CAN HAVE A NULL COMPLEMENT* and there is one passage I do not understand. I believe that he ...
Kadmos's user avatar
  • 3,801
3 votes
2 answers
208 views

I am doing an expository presentation on the theorem, and I understand the proof. What I fail to understand is, why is this theorem important? Why does any sequence $\{f_n\}$ containing a uniformly ...
Educational_Frosting's user avatar
1 vote
1 answer
75 views

I'm on my first semester of the Functional Analysis course that we have in my university. I've been stuck on this particular problem our professor presented to us not long ago for a while now: Let $...
Pabloo's user avatar
  • 121
3 votes
1 answer
80 views

**My apologies in advance if this question is elementary, the reason I fear that it may be trivial is that I do not know some concrete examples of elements of $BH(\mathbb{D})\setminus A(\...
Ali Taghavi's user avatar
4 votes
1 answer
110 views

There is this thing regarding this topic that confuses me, and I am afraid I am wrong about it, because as you know math has a lot of hidden details. Let $(X,\Sigma,\mu)$ be a measure space, $\mu(E)=0$...
Unknown 21103907's user avatar
0 votes
0 answers
34 views

A vector space can has different norms. A sequence can converge in a norm, but diverge in another norm. However, can there be: A vector space $V$ Two norms $\left\| \cdot \right\|_1$, $\left\| \cdot \...
user1596524's user avatar

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