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Questions tagged [modular-forms]

A modular form is a (complex) analytic function on the upper half-plane satisfying a certain kind of functional equation with respect to the group action of the modular group.

3 votes
1 answer
412 views

I have been wondering this for a while; I get how elliptic curves of the Weierstrass form $y^2=4x^3-g_2x-g_3$ have the lowest degree and are the simplest way to study a genus $1$ curve. But why aren’t ...
Roccooi's user avatar
  • 360
3 votes
2 answers
130 views

I'm studying modular forms and reading Tom M. Apostol's book. I'm studying this modualr form: $\eta(\tau)=e^{\frac{\pi i\tau}{12}}\prod_{n=1}^{\infty}(1-e^{2\pi in\tau}).$ I am trying to prove the ...
idk's user avatar
  • 33
1 vote
1 answer
141 views

Let $p$ be a prime, and let $E/\mathbb{Q}$ and $F/\mathbb{Q}$ be elliptic curves. Suppose the modular forms $f$ attached to $E$ and $g$ attached to $F$ have $q$-expansions that agree modulo $p$ in ...
Poitou-Tate's user avatar
  • 6,877
2 votes
1 answer
84 views

Let $p$ be a prime. Let $E$ and $F$ be elliptic curves over $\mathbb{Q}$, and let $f_E$ and $f_F$ denote the associated modular forms. Suppose that all Fourier coefficients are congruent modulo $p$, i....
Poitou-Tate's user avatar
  • 6,877
3 votes
0 answers
61 views

I will share the formula for the Hecke operator as given in A First Course in Modular Forms by Fred Diamond and Jerry Shurman. Proposition 5.2.1. Let $N \in \mathbb{Z}^+$, let $\Gamma_1 = \Gamma_2 = \...
Math Admiral's user avatar
  • 1,783
4 votes
1 answer
189 views

Let $K$ be a number field, and let $G_K$ be its absolute Galois group. Let $f$ be a normalized Hecke eigenform of weight $k( \geq 2)$, level $N$, and character $\chi$. Let $p$ be a rational prime with ...
Blue_Sky's user avatar
1 vote
0 answers
42 views

Let $X(p)$ be the mudular curve over ${\Bbb Q}(\zeta_p)$. Suppose ${\frak X}(p)$ is the regular model over ${\Bbb Z}(\zeta_p)$. If we consider the mod ${\frak p}$ reduction of ${\frak X}(p)$ over ${\...
Pierre MATSUMI's user avatar
2 votes
0 answers
55 views

I have a question about a step in the proof of Proposition 3.3.2 in Goldfeld's book Automorphic forms and L-functions for the group $\textrm{GL}_n(\mathbb R)$. If $f$ is a Maass form for $\textrm{SL}...
dekimashita's user avatar
2 votes
1 answer
67 views

Suppose that $f$ is a half-integral-weight $GL_2$ Maass form of level $q$ and nebentypus $\chi$. If $\rho_f(m)$ denotes the $m^{th}$ Fourier coefficient of $f$, then it is known that $$\rho_f(-m)=\pm\...
Troy W.'s user avatar
  • 255
1 vote
1 answer
56 views

I am learning about modular forms and modular functions, and in working out the nitty-gritty details, I have stumbled on the following question: Is it possible to find an $\operatorname{SL}_2(\mathbb{...
stillconfused's user avatar
16 votes
1 answer
752 views

When playing around with modular form integrations, one may accidentally come across the following mysterious integral: \begin{align*} I=\int_0^{i\infty}\frac{E_4(z)}{\sqrt{j(z)}}dz\approx 0....
cybcat's user avatar
  • 1,064
1 vote
0 answers
69 views

Authors's Reasoning: Definition 1.3.4. A nonzero holomorphic homomorphism between complex tori is called an isogeny. In particular, every holomorphic isomorphism is an isogeny. Every isogeny surjects ...
Luca Hao's user avatar
  • 327
2 votes
0 answers
177 views

I am looking at the Lambert-type series $$ S(q)=\sum_{n\ge1} n\,q^{n^2}\qquad (q=e^{2\pi i\tau},\ \Im\tau>0), $$ and I found that it admits a representation connected to Zwegers’ $\mu$-function. I ...
stocha's user avatar
  • 781
0 votes
0 answers
34 views

Let $f \in S_2(\Gamma_0(N))$ be a primitive form (newform + normalized eigenform), $A_f$ the attached abelian variety over $\mathbb{Q}$, $K$ the number field of $f$ and suppose that the coefficients ...
supermartruc's user avatar
1 vote
1 answer
57 views

I've been looking at the function $$f(z) = \sum_{n=1}^\infty \left(n-\frac{1}{2}\right) e^{i\pi \left(n-\frac{1}{2}\right)^2 z}$$ for $z$ in the upper half-plane, which is formally related to the half-...
EthanK's user avatar
  • 305

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