Questions tagged [quadrilateral]
For questions about general quadrilaterals (including parallelograms, trapezoids, rhombi) and their properties.
771 questions
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How to prove that four points are concyclic under these given conditions?
I've stumbled upon the following problem that made me curious for quite a while. Below is one of many possible diagrams of the problem in question.
Given that $ABCD$ is a parallelogram with acute ...
5
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4
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How to construct the following isosceles trapezoid with compass and a straightedge?
Given:
$ABCD$ is an isosceles trapezoid with $BC \parallel AD$.
$MN$ is a segment such that $M\in AB$, $N\in CD$, $BC\parallel MN\parallel AD$.
$AM : MB = DN : NC = 1 : 2$.
$MN = AB = CD$.
$O$ is a ...
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Non-concyclicity of the circumcenters of complementary triangles in a quadrilateral
About a year ago, I discovered a property related to quatrains, but I haven't been able to prove it. The property is rather strange, and I don't know where to begin proving it. If anyone can help me, ...
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What is the length of side AB in quadrilateral ABCD circumscribed about semicircle (O)?
Here's a problem I just came up with :
A semicircle (O) is inscribed in a quadrilateral ABCD , as shown in the figure.
If sides AD , DC , CB measure 17 ; 16 and 14 respectively, what is the length of ...
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How can this theorem be proven geometrically?
Here's a problem I just came up with:
A chord, passing through the point of intersection of the two diagonals of a cyclic quadrilateral $ABCD$, intersects the circumcircle at $N$ and $P$, as shown in ...
2
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1
answer
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A square configuration leading to an isosceles trapezoid and $FB =\frac{na}{(2n+1)(n+1)}$
Let ABCD be a square with side length $a$. Let $M$ be a point on $BC$. The line $AM$ meets the diagonal $BD$ at $K$. From $K$ draw the perpendicular $KL$ to $CD$, with foot $L$. Let $P$ be the ...
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Prove that diagonals of a cyclic quadrilateral bisects the angle subtend by the midpoint with opposite vertices in harmonic quadrilateral
$ABCD$ is a cyclic quadrilateral. The midpoints of the diagonals $AC$ and $BD$ are respectively $P$ and $Q$. If $BD$ bisects $\angle AQC$, the prove that $AC$ will bisect $\angle BPD$
Source- NMTC ...
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Vertices of quadrilaterals as circumcenters
Let $ABCD$ be a quadrilateral. Do there exist points $P,Q,R,S$ such that $A,B,C$ and $D$ are the respective circumcenters of $\triangle QRS$, $\triangle RSP$, $\triangle SPQ$ and $\triangle PQR$?
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How to calculate the area of a quadrilateral given the (x,y) coordinates of its vertices
This problem is from the 2017 Gauss Contest (Grade 7).
Four vertices of a quadrilateral are located at (7,6), (−5,1), (−2,−3), and (10,2).
What is the area of the quadrilateral in square units?
I ...
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Divide a right triangle into three quadrilaterals of equal area
The goal is to find the point $M$ inside a given right triangle $ABC$ such that $\operatorname{Area}(APMN)=\operatorname{Area}(CQMP)=\operatorname{Area}(BQMN)$, where $N$, $P$, and $Q$ are the ...
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Potentially new formula for the area of a general quadrilateral using all its sides and any one angle
I think this is a potentially new formula for the area of a general quadrilateral. Also do note this post has been repurposed for combining all my 4 posts regarding my formula as they were being ...
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Prove concyclic points using Ptolemy's trigonometric theorem
Let $\triangle ABC$ be a scalene triangle with point $D$ inside it. Let $AD$, $BD$ and $CD$ intersect $BC$, $CA$ and $AB$ in $M$, $N$ and $O$. Let the midpoint of the segment that connects the ...
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Is this formula correct for the area of any non self intersecting quadrilateral?
$$
\Delta=\frac{1}{2}\left[ab \sin \theta + cd \sqrt{1- \left(\frac {c^2+d^2-a^2-b^2+2ab\cos\theta}{2cd}\right)^2} \right]
$$
This is the formula that I've proven to be able to find the area of any ...
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New potential formula for calculating the area of any general quadrilateral
This link shows the derivation of this formula for a concave quadrilateral.
This link shows the derivation of this formula for a convex quadrilateral.
The formula I'm talking about is:
$$
\frac{1}{2}\...
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The incenter of a quadrilateral is a rational function of the vertex coordinates
Given only the coordinates of $A,B,C,D$, the incenter can be recovered purely by reflections across diagonals and perpendicular constructions, without ever touching angle bisectors.
Take diagonal $AC$...