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Questions tagged [quadrilateral]

For questions about general quadrilaterals (including parallelograms, trapezoids, rhombi) and their properties.

4 votes
3 answers
158 views

I've stumbled upon the following problem that made me curious for quite a while. Below is one of many possible diagrams of the problem in question. Given that $ABCD$ is a parallelogram with acute ...
TheProver's user avatar
  • 429
5 votes
4 answers
362 views

Given: $ABCD$ is an isosceles trapezoid with $BC \parallel AD$. $MN$ is a segment such that $M\in AB$, $N\in CD$, $BC\parallel MN\parallel AD$. $AM : MB = DN : NC = 1 : 2$. $MN = AB = CD$. $O$ is a ...
TheProver's user avatar
  • 429
0 votes
2 answers
90 views

About a year ago, I discovered a property related to quatrains, but I haven't been able to prove it. The property is rather strange, and I don't know where to begin proving it. If anyone can help me, ...
زكريا حسناوي's user avatar
7 votes
2 answers
345 views

Here's a problem I just came up with : A semicircle (O) is inscribed in a quadrilateral ABCD , as shown in the figure. If sides AD , DC , CB measure 17 ; 16 and 14 respectively, what is the length of ...
Jamil Sanjakdar's user avatar
4 votes
1 answer
364 views

Here's a problem I just came up with: A chord, passing through the point of intersection of the two diagonals of a cyclic quadrilateral $ABCD$, intersects the circumcircle at $N$ and $P$, as shown in ...
Jamil Sanjakdar's user avatar
2 votes
1 answer
122 views

Let ABCD be a square with side length $a$. Let $M$ be a point on $BC$. The line $AM$ meets the diagonal $BD$ at $K$. From $K$ draw the perpendicular $KL$ to $CD$, with foot $L$. Let $P$ be the ...
Stelios Petrolekas's user avatar
2 votes
1 answer
102 views

$ABCD$ is a cyclic quadrilateral. The midpoints of the diagonals $AC$ and $BD$ are respectively $P$ and $Q$. If $BD$ bisects $\angle AQC$, the prove that $AC$ will bisect $\angle BPD$ Source- NMTC ...
JKH_Mathematics's user avatar
2 votes
1 answer
74 views

Let $ABCD$ be a quadrilateral. Do there exist points $P,Q,R,S$ such that $A,B,C$ and $D$ are the respective circumcenters of $\triangle QRS$, $\triangle RSP$, $\triangle SPQ$ and $\triangle PQR$? ...
JKH_Mathematics's user avatar
14 votes
6 answers
3k views

This problem is from the 2017 Gauss Contest (Grade 7). Four vertices of a quadrilateral are located at (7,6), (−5,1), (−2,−3), and (10,2). What is the area of the quadrilateral in square units? I ...
Will.Octagon.Gibson's user avatar
7 votes
2 answers
366 views

The goal is to find the point $M$ inside a given right triangle $ABC$ such that $\operatorname{Area}(APMN)=\operatorname{Area}(CQMP)=\operatorname{Area}(BQMN)$, where $N$, $P$, and $Q$ are the ...
Jamil Sanjakdar's user avatar
2 votes
1 answer
166 views

I think this is a potentially new formula for the area of a general quadrilateral. Also do note this post has been repurposed for combining all my 4 posts regarding my formula as they were being ...
PARTH PATEL's user avatar
6 votes
0 answers
163 views

Let $\triangle ABC$ be a scalene triangle with point $D$ inside it. Let $AD$, $BD$ and $CD$ intersect $BC$, $CA$ and $AB$ in $M$, $N$ and $O$. Let the midpoint of the segment that connects the ...
Nineta's user avatar
  • 613
5 votes
0 answers
119 views

$$ \Delta=\frac{1}{2}\left[ab \sin \theta + cd \sqrt{1- \left(\frac {c^2+d^2-a^2-b^2+2ab\cos\theta}{2cd}\right)^2} \right] $$ This is the formula that I've proven to be able to find the area of any ...
PARTH PATEL's user avatar
0 votes
0 answers
166 views

This link shows the derivation of this formula for a concave quadrilateral. This link shows the derivation of this formula for a convex quadrilateral. The formula I'm talking about is: $$ \frac{1}{2}\...
PARTH PATEL's user avatar
1 vote
2 answers
193 views

Given only the coordinates of $A,B,C,D$, the incenter can be recovered purely by reflections across diagonals and perpendicular constructions, without ever touching angle bisectors. Take diagonal $AC$...
hbghlyj's user avatar

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