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Questions tagged [lorentz-transformation]

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0 answers
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We know that finite-dimensional representations of the Lorentz group are non-Hermitian, i.e. spinor representation generators $S^{\mu\nu}$ satisfy the relation $S^{0i\dagger}=-S^{0i}$. But for ...
CSYin's user avatar
  • 21
2 votes
1 answer
137 views

The book "Groups, Representations and Physics" by Jones says on p.208 [...] the generators of boosts $\textbf{Y}$ are anti-Hermitian. Hence when exponentiated they produce anti-unitary ...
Apple Py's user avatar
  • 101
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1 answer
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Many books prove that the magnetic and electric forces are the same thing observed by two different observers of two specific frames. Many books take the example of two wires carrying same current,...
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12 votes
2 answers
647 views

I'm confused, given the equal time commutation relations in scalar field theory: $$[\phi(\vec x,t),\pi(\vec{x}',t)]=i\hbar{\bf 1}\delta^3(\vec x -\vec{x}').$$ I thought that in special relativity, we ...
Lotus's user avatar
  • 123
1 vote
2 answers
118 views

We have the formula for gamma matrices as \begin{equation} S \gamma^\mu S^{-1} = \Lambda ^\mu{}_\nu \gamma^\nu . \end{equation} Here is the $\Lambda$ performing Lorentz transformation on the gamma ...
Vasker Keisham's user avatar
3 votes
2 answers
221 views

According to books and lecture notes, $$\Lambda^{-1}=\eta^{-1}\Lambda^T\eta=\eta\Lambda^T\eta$$ which I have no problem with. Then they write this in index notation as $$(\Lambda^{-1})^{\mu}_{\,\,\nu}=...
Başar Görgün's user avatar
4 votes
1 answer
175 views

I am trying to understand, at a technical level, how the Wigner (Thomas) rotation arises from the composition of non-collinear Lorentz boosts, and I am encountering what appears to be an ambiguity ...
Vivek Kalita's user avatar
5 votes
2 answers
295 views

Last night, I found an interesting way of deriving the Lorentz transformation, but I never saw that approach before. So I'm wondering if this demonstration is sound, and if it was already considered ...
Cham's user avatar
  • 8,117
1 vote
0 answers
47 views

I am learning about four-vectors in special relativity in my electrodynamics lecture. We have learned that under Lorentz transformations $\Lambda$, vectors transform like $$ x'^{\mu} = \Lambda_{~~~\nu}...
phgil's user avatar
  • 11
8 votes
1 answer
492 views

I am currently studying the Lorentz group, and I am particularly interested in learning about its Lie algebra, $\mathfrak{so}(1, 3)$ (I have learned it doesn't really matter whether we are talking ...
Lagrangiano's user avatar
  • 3,044
3 votes
1 answer
196 views

I know that questions on this topic has been asked before, but I would like to present specifically my confusion about this topic. Let's first start with the distinction between active and passive ...
Stallmp's user avatar
  • 931
3 votes
1 answer
178 views

I've been told that a Lorentz invariant or something that goes unaffected after Lorentz transformations are scalars. Now, I never really gave too much thought into it, but I now realise... Aren't $x,y,...
Ivy's user avatar
  • 175
6 votes
6 answers
1k views

I do understand the math part of the transformation, but I have a problem understanding why exactly there will be a "triangle" (to say it simply). Pretty much all the textbooks and videos ...
Eduard's user avatar
  • 69
5 votes
1 answer
285 views

Exercise 7.25 in Freedman & Van Proeyen's Supergravity is the following Show that $D_\mu \Psi$ also transforms as a spinor, namely into $\exp(− 1/4 \lambda^{ab}(x)\gamma_{ab}) D_\mu \Psi(x)$. You ...
Geigercounter's user avatar
-4 votes
1 answer
166 views

An object moving relative to an observer experiences time dilation, as stated in the theory of Special Relativity. But suppose only time dilation occurred while lengths remained unchanged. Wouldn’t ...
Optimus Prime's user avatar

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