bash script loop multiple variables

To be generic, you can use 'length' as shown below.

#!/bin/bash

# Define the arrays
array1=("a" "b" "c" "d")
array2=("w" "x" "y" "z")

# get the length of the arrays
length=${#array1[@]}
# do the loop
for ((i=0;i<=$length;i++)); do
        echo -e "${array1[$i]} : ${array2[$i]}"
done

You can also assign the array like the following

array1=`awk -F" " '$1 == "CLIENT" { print $2 }' clientserver.lst`

You can use arrays for that:

A=({a..z}) B=({1..26})
for (( I = 0; I < 26; ++I )); do
    echo "/dev/sd${A[I]}               /disk${B[I]}                                 ext4     noatime        1 1" >> test
done

Example output:

/dev/sda               /disk1                                 ext4     noatime        1 1
...
/dev/sdz               /disk26                                 ext4     noatime        1 1

Update:

As suggested you could just use the index for values of B:

A=('' {a..z})
for (( I = 1; I <= 26; ++I )); do
        echo "/dev/sd${A[I]}               /disk${I}                                 ext4     noatime        1 1" >> test
    done

Also you could do some formatting with printf to get a better output, and cleaner code:

A=('' {a..z})
for (( I = 1; I <= 26; ++I )); do
    printf "%s%20s%15s%15s%4s%2s\n" "/dev/sd${A[I]}" "/disk${I}" ext4 noatime 1 1 >> test
done

Also, if you don't intend to append data to file, but only write once every generated set of lines, just make redirection by block instead:

A=('' {a..z})
for (( I = 1; I <= 26; ++I )); do
    printf "%s%20s%15s%15s%4s%2s\n" "/dev/sd${A[I]}" "/disk${I}" ext4 noatime 1 1
done > test