1

How to set shell variables from an input file ?

hello,

I need to set dynamic variable from an .ini file in a shell script.

Assume the input file is input.ini :

var1=val1
var2=val2
var3=val3

In a script I want to set var1, var & var3 respectively to their val1, val2 & val3 to get

echo $var1
val1
echo $var2
val2
...

I've tryed :

file="input.ini"
while IFS== read -r f1 f2
do
   eval dynvar=$f1
   dynvar=$f2    
done <"$file"

echo $var1
echo $var2
echo $var3

the echo $varx commands give no output. How can I work it out ?

thanks in advance.

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2 Answers 2

Reset to default
1 
source input.ini

Or

. input.ini

More info

<source | .> filename [arguments]
    Execute commands from a file in the current shell.
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1 Comment

Thanks for your answer but I don't understand what you mean ... and in fact I fixed the problem after searching the web (I've never written this kind of code). See next answer
0

Solved

using :

file="install.ini"
while IFS== read -r f v
do
  eval "$f=$v"   
done <"$file"

did the trick.

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3 Comments

Why do it manually when it can be done using a shell command like source as indicated in previous answer?
.. because I don't understand how it works .. I read it's used to execute a file passed as argument but I don't see the relationship with my question ...
executes commands from a file, in your case the variable assignments

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