How to get list elements by matching string using scala?

Question

I have following list-

List((name1,233,33),(name2,333,22),(name3,444,55),())

I have another string which I want to match with list and get matched elements from list. There will be only one element in list that matches to given string.

The list may contains some empty elements as given as last element in above list.

Suppose I am maching string 'name2' which will occurs only once in the list, then My expected output is -

List(name2,333,22)

How do I find matching list element using scala??

Should the output be List(name2,333,22) or really List((name2,333,22)) ? — Michael Zajac
– Michael Zajac, Commented Nov 11, 2014 at 14:04
Although this problem is solveable, it can be much easier and cleaner if you don't mix types in a List. May be there is another way to construct this List so that it is of type: List[(String, Int, Int)], not List[Any]. — ka4eli
– ka4eli, Commented Nov 12, 2014 at 21:15

Gabriele Petronella · Accepted Answer · 2014-11-11 10:08:02Z

6

.find(_._1 == name2)

will be better

edited Nov 11, 2014 at 10:08

Gabriele Petronella

108k21 gold badges223 silver badges238 bronze badges

answered Nov 11, 2014 at 10:07

Evgeny Vanslov

734 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

elm · Accepted Answer · 2014-11-11 10:08:57Z

4

Consider collect over the tuples list, for instance like this,

val a = List(("name1",233,33),("name2",333,22),("name3",444,55),())

Then

a collect {
  case v @ ("name2",_,_) => v
}

If you want only the first occurrence, use collectFirst. This partial function ignores tuples that do not include 3 items.

answered Nov 11, 2014 at 10:08

elm

20.5k15 gold badges72 silver badges116 bronze badges

Collectives™ on Stack Overflow

How to get list elements by matching string using scala?

2 Answers 2

Comments

Comments

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Related