PHP Code Within PHP Include

Question

I'm creating a php page and I'm using include statements to load the contents but it's having a bad effect on the output. Here are my files:

index.php:

<div class="sectionSpacer"></div>
<?php include("newsection.php"); ?>
<div class="sectionSpacer"></div>

newsection.php:

<div class="sectionInner">
    <div id="details">
        <?php echo $details; ?>
    </div>
</div>

$details:

My email address is <?php echo $my_email; ?>

The problem is that while the div is being displayed, $details isn't echoing out the email address on the index page. How can this be resolved?

As long as it is defined, my answer should display your email address — Drakes
– Drakes, Commented Apr 5, 2015 at 14:57

Pushkar · Accepted Answer · 2015-04-05 15:37:33Z

2

Modify ur newsection.PHP to following:

<?php

$txt= <<< EOPAGE
<div class="sectionInner">
<div id="details">
    $details
</div>
</div>
 EOPAGE;

echo $txt;
?>

The declaration of variables details and my_mail:

   $my_email= "some.email@example. com;
   $details="My email address is". $my_email;

I am sure this will work

edited Apr 5, 2015 at 15:37

answered Apr 5, 2015 at 14:19

Pushkar

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Comments

Drakes · Accepted Answer · 2015-04-06 06:36:57Z

1

In the case you are trying to echo the string $details of mixed HTML/PHP (like from a database), you can echo it this way:

echo eval(' ?>'.$details.'<?php ');

Then change your code to this:

<div class="sectionInner">
    <div id="details">
        <?php echo eval(' ?>'.$details.'<?php '); ?>
    </div>
</div>

Of course if you can rework your setup to avoid eval'ing PHP code, please, please do that.

edited Apr 6, 2015 at 6:36

answered Apr 5, 2015 at 14:28

Drakes

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1 Comment

Drakes Over a year ago

How did this work out for you? Were you able to try it with your code and verify that it works for you?

Joshua Byer · Accepted Answer · 2015-04-05 13:17:05Z

0

What you are trying to do cannot be done, and you should know this if you understand how code is executed. put -myemail- into

$variable = "my email is -myemail-";
$variable = str_replace($variable,"-myemail-",$myemail);
echo $variable;

edited Apr 5, 2015 at 13:17

answered Apr 5, 2015 at 12:38

Joshua Byer

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8 Comments

Foot Promoter Over a year ago

Ok, What about if the echoed $details contains a <?php ?> statement. That's what isn't showing up - how can this be corrected?

Joshua Byer Over a year ago

try escaping it, that is a weird case.

Foot Promoter Over a year ago

Take a look at my updated question! How do I escape?

Foot Promoter Over a year ago

I'm sorry but can you show how that would work on my original post code?

Foot Promoter Over a year ago

I'm sorry but that doesn't really make sense to me. $details IS being echoed but the email isn't, as stated in my question.

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