PHP - returning a variable variable from a function scope

Question

Is there a way to return a variable variable from a function?

This is what I tried:

function varvar($num){
    $var = "foo".$num;
    return $$var;
}
varvar(3);
echo $foo3;

But nothing prints out. Any ideas?

John Conde · Accepted Answer · 2016-07-24 00:18:13Z

2

You need to capture the return value in a variable:

function varvar($num){
    $var = "foo".$num;
    return $$var;
}
$foo3 = varvar(3);
echo $foo3;

answered Jul 24, 2016 at 0:18

John Conde

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