How to match and remove any line containing a specific string?

Question

I have a huge directory list of URLs from my Web site. Example:

/folder/folder2/folder3/page.htm
/folder/folder2/folder3/page2.htm
/folder/folder2/folder3/page3.htm
/folder/folder2/folder3/page4.htm

I want to clean this list of all items that have /folder2 in the path. I need a regular expression to perform a find and replace for everything that uses /folder2/ and delete those lines from my list. So find/replace it with blank.

Does anyone know what the proper regular expression for this would be? I should specify I am using Dreamweaver as my editor, which may use different regular expressions.

Chris B. Behrens · Accepted Answer · 2011-01-21 21:13:54Z

7

This expression will match the entire line such that the string "/folder2" occurs in it:

^.+?\/folder2/.+$

HTH.

answered Jan 21, 2011 at 21:13

Chris B. Behrens

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4 Comments

Josh Bevins Over a year ago

Hi - this didn't work in Dreamweaver. Sorry I should have specified that was the program I am using. Maybe the regular expressions are different in Dreamweaver?

Chris B. Behrens Over a year ago

Hmmm...shouldn't be. This is plain-vanilla regex. Maybe it doesn't like my second forward-slash, which is unescaped...try this: ^.+\/folder2\/.+$.

Josh Bevins Over a year ago

Nothing with that either. I have the "Use regular expressions" box checked as well, so it's just not finding any matches.

Chris B. Behrens Over a year ago

Simplified even further: .+/folder2/.+

Santiago Alessandri · Accepted Answer · 2011-01-21 21:21:05Z

0

In Python that would be:

import re
regex = re.compile('.*/folder2/.*')
f = open("filtered_file.txt", "w")
map(lambda x: f.write(x), filter(lambda x: not regex.match(x), open("input.txt")))
f.close()

answered Jan 21, 2011 at 21:21

Santiago Alessandri

6,88532 silver badges49 bronze badges

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