Say I have an array called a.
$a = array(1=>'one',2=>'two');
and another array $b
$b = array(a => $a); This doesnt work while,
$b = array(a => array(1=>'one',2=>'two')); works.
5 Answers
Enclose the key in quotes like this:
$b = array('a' => $a);
A key may be either an integer or a string. If the key is a string, it must be enclosed in quotes, which your code is missing.
See the fixed code working in action here.
1 Comment
Spudley
+1, correct. but specifically, non-numeric keys are strings, and must be in quotes. (user already has numeric keys working without quotes, which is fine)
Unable to replicate. Both of your examples "work" for me, in the sense that they produce a data structure of:
Array
(
[a] => Array
(
[1] => one
[2] => two
)
)
However, you shouldn't be using a as a bareword, i.e. it should be:
$b = array('a' => $a);
Possibly in your actual code this is causing you trouble; I can't say for sure because your made-up example doesn't actually generate the failure.
Comments
just tested it it should work, have a look at the link
Comments
For debugging always set error_reporting(E_ALL);. In your case, the reason why it's not working would be displayed.
You have to quote a => 'a'.
Comments
Though shamittomar is correct that you should enclose your string array indexes with quotes, PHP magically turns undefined constants (your strings without quotes) into strings, which creates a warning but still runs your code. I tried all the examples on http://writecodeonline.com/php/ and they worked fine!
$b = array('a' => $a);should work; string array keys must be enclosed in quotes