php access property of object in array

Question

I have a php variable that I got from a _POST. var_dump shows this:

array(9) { [0]=> array(2) { ["age"]=> string(2) "62"
["amount"]=> string(5) "10878" } [1]=> array(2) { ["age"]=> string(2) "63"
["amount"]=> string(5) "10878" } [2]=> array(2) { ["age"]=> string(2) "64"
["amount"]=> string(5) "10878" } [3]=> array(2) { ["age"]=> string(2) "65"
["amount"]=> string(5) "10878" } [4]=> array(2) { ["age"]=> string(2) "66"
["amount"]=> string(5) "10878" } [5]=> array(2) { ["age"]=> string(2) "67"
["amount"]=> string(5) "28416" } [6]=> array(2) { ["age"]=> string(2) "68" 
["amount"]=> string(5) "28416" } [7]=> array(2) { ["age"]=> string(2) "69" 
["amount"]=> string(5) "28416" } [8]=> array(2) { ["age"]=> string(2) "70" 
["amount"]=> string(5) "28416" } }

I loop through the array but can't get the properties to print:

for ($i=0; $i<count($incomeSched); $i++) {
    $age = $incomeSched[$i]->age;
    $amt = $incomeSched[$i]->amount;
    echo "age=$age, amount=$amt<br>";
}

age and amount are blank:

age=, amount=

Currently on mobile but have you tried $incomeSched[$i]['age']? — Isitar
– Isitar, Commented Jun 3, 2018 at 0:10

Michael Beeson · Accepted Answer · 2018-06-03 00:31:02Z

0

There's a difference between associative arrays and objects.

$incomeSched[$i]->age;

is what you'd do to access the property of an object. For an associative array you'd want

$incomeSched[$i]["age"]

You can cast an array as an object if need be:

$obj = (object)$incomeSched;

learn more here:

PHP - associative array as an object

answered Jun 3, 2018 at 0:31

Michael Beeson

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Comments

AmShaegar · Accepted Answer · 2018-06-03 00:28:47Z

0

As far as I remember ->age is object syntax. You need array syntax which would be ['age'].

for ($i=0; $i<count($incomeSched); $i++) {
    $age = $incomeSched[$i]['age'];
    $amt = $incomeSched[$i]['amount'];
    echo "age=$age, amount=$amt<br>";
}

answered Jun 3, 2018 at 0:28

AmShaegar

1,53911 silver badges18 bronze badges

1 Comment

user3217883 Over a year ago

Thank you. You are right but so was @Michael Beeson and he gave a little more info that will help others searching for this so I gave him the credit for the answer.

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