Typescript array initializing

Question

let s:number[][];

How can I fill this s matrix as 0 of n * n.

[[0, ..., 0], [0, ..., 0] ... [0, ..., 0]]

This is what I'm doing

for(let i = 0;i < n;i ++) {
    let ss = [];
    for(let j = 0;j < n ;j ++)   ss.push(0);
    s.push(ss);
}

It's working but is there any more efficient and sophisticated way?

Eugene Karataev · Accepted Answer · 2020-04-24 13:34:35Z

2

You can use Array's fill method:

s = new Array(n).fill(new Array(n).fill(0));

answered Apr 24, 2020 at 13:34

Eugene Karataev

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StepUp · Accepted Answer · 2020-04-24 14:05:38Z

1

Try to use the Array.from:

fillTwoDArray = (rows, columns,  defaultValue) => {
      return Array.from({ length:rows }, () => (
          Array.from({ length:columns }, ()=> defaultValue)
       ))
    }

console.log(fillTwoDArray(3, 7, 'foo'))

edited Apr 24, 2020 at 14:05

answered Apr 24, 2020 at 13:45

StepUp

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Comments

Mohammad Usman · Accepted Answer · 2020-04-24 13:38:14Z

1

const s = [...Array(n)].map(e => Array(n).fill(0))

I'm using this way!

edited Apr 24, 2020 at 13:38

Mohammad Usman

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answered Apr 24, 2020 at 13:34

True

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