Python Tkinter IndexError: List out of range

Question

I am making a meal planning application that allows you to set ingredients you have and recipes and gives you a grocery list based on it. When I run it, however, I get these errors:

IndexError: list index out of range 
Exception in Tkinter callback
...
Line 15: recipes[row-1].append(recipeIngredient): IndexError: list index out of range
File "/Users/*****/Documents/shopping planner.py"

I have looked at this question, but it doesn't answer my question: Python - IndexError: list index out of range
Here's my code:

def MkRecipe():
    recipe_creator = tkinter.Button(window, text=" ", command=MkIngredient(len(recipes)))
    recipe_creator.grid(row=1, column=(len(recipes)+1))
    recipes.append([])
def mkIngredient(row):
    recipeIngredient = tkinter.Entry()
    recipes[row-1].append(recipeIngredient)
    recipeIngredient.grid(row=len(recipes[row]), column=row)

Can you post the entire error? I think you've cropped out the useful info. — puppydog
– puppydog, Commented May 7, 2020 at 13:13
I'll try. Some technology problems are preventing me from copying and pasting — ARI FISHER
– ARI FISHER, Commented May 7, 2020 at 13:15

ARI FISHER · Accepted Answer · 2020-05-07 13:38:55Z

2

Use ln = len(recipe),recipe_creator = tkinter.Button(text=" ", command=lambda: MkIngredient(ln)), and recipeIngredient.grid(row=len(recipes[row-1])+1, column=row). The problem is that you are running the function on button creation.

edited May 7, 2020 at 13:38

ARI FISHER

3512 silver badges14 bronze badges

answered May 7, 2020 at 13:19

rizerphe

1,3961 gold badge17 silver badges26 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Python Tkinter IndexError: List out of range

1 Answer 1

Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Linked

Related