I wanted to ask. if there is an efficient way to split a string and ignore inner strings of is
Example: I get a string in this format:
s = 'name,12345,Hello,\"12,34,56\",World'
and the output I want, is:
['name', '12345', 'Hello', "12,34,56", 'World']
by splitting at the "," the numbers become separated:
['name', '12345', 'Hello', '"12', '34', '56"', 'World']
I know I could split at \" and split the first and the third part separately, but this seems kind of inefficient to me
This job belongs to the csv module:
import csv
out = next(csv.reader([s], skipinitialspace=True))
# out is
# ['name', '12345', 'Hello', '12,34,56', 'World']
Notes
csv library deals with comma-separated values, perfect for this jobcsv.reader takes in a sequence of texts (i.e. lines of text)skipinitialspace flag is just that: it tells the reader to skip initial spaces before each valueIf your string separates each element with a comma and a space you could pass ", " to your split method like this:
>>> s = 'name, 12345, Hello, \"12,34,56\", World'
>>> print(s.split(", "))
['name', '12345', 'Hello', '"12,34,56"', 'World']
You can try built-in csv module to parse the string:
import csv
from io import StringIO
s = 'name, 12345, Hello, "12,34,56", World'
print(next(csv.reader(StringIO(s), skipinitialspace=True)))
Prints:
['name', '12345', 'Hello', '12,34,56', 'World']
