Bash script works via terminal but not via main menu

Question

When I run a bash script from terminal or nautilus, it works properly, but when I run it via gnome's 'Main Menu', it returns an error.

read -p "" -n1 selection

This is the line, that return the following error:

/usr/local/bin/php-version.sh: 9: read: Illegal option -n

But when I run the script via terminal (./file.sh), there's no problem with this

The Main Menu entry is bash usr/local/bin/php-version.sh

File permissions are 755, owner is root.

EDIT:

/usr/local/bin/php-version.sh

#!/bin/bash

sudo echo -e "sudo/root permission: \e[32mOkay\e[0m"

echo -e "Type \e[2m5\e[0m to change from php version \e[1m7 \e[0mto \e[1m5\e[0m"
echo -e "Type \e[2m7\e[0m to change from php version \e[1m5 \e[0mto \e[1m7\e[0m"

echo -en "\e[1mSelect: \e[0m"
read -p "" -n1 selection
echo

case "$selection" in
    "5") 
        sudo a2dismod php7.0 >> /dev/null
        sudo a2enmod php5 >> /dev/null
        sudo a2query -m php5
        ;;
    "7")
        sudo a2dismod php5 >> /dev/null
        sudo a2enmod php7.0 >> /dev/null
        sudo a2query -m php7.0
        ;;
    *)
        sudo echo -e "\e[91mInvalid input: \e[39m$selection\e[0m"
        echo -en "\e[2mPress Enter..."; sed -n q </dev/tty
        exit 1
        ;;
esac

echo "Restarting apache2..."; sudo service apache2 restart    
echo -en "\e[2mPress Enter..."; sed -n q </dev/tty

/usr/local/bin/test.sh (where the read command always works)

#!/bin/bash

ps aux | grep $$ | grep -v grep

read -p "" -n1 test

echo -e "\n"

env

$SHELL

Answer 1

I don't really see why read "" -n1 selection works in terminal and not from the menu. The error message seems misleading too. However the correct bash syntax should be

read -n 1 selection

You may change that line in php-version.sh.

Beside that the whole scripts looks a bit strange. Most of the sudo commands should not be sudo. Anyways that wasn't the question.