$ tail -f /logs/filename.log | awk '!(/list)'
I am able to run this command in GNU Linux flavour
But when I written in a script it is not working.
test.ksh:
variable="/logs/filename.log | awk '!(/list)'"
tail -f $var
Getting the error as
tail: cannot open `|' for reading: No such file or directory
tail: cannot open `grep' for reading: No such file or directory
tail: cannot open `list' for reading: No such file or directory
How is need to work on this? Can anyone guide on this?
Your code is broken in a couple of ways...
You define a variable with the name variable, then call it with the name var. That won't work.
I can't make out what you were trying to accomplish with the variable in the first place because the quoting is so screwy. The interpreter will have the more problems than I did ;-) In effect, you are sending a string that looks like a set of commands including a pipeline -- but since they are inside of a quoted string as an argument to another command, they will just come across as so many characters in a text blob as an argument. Not something the interpreter will touch.
Perhaps you want something like this in your test.ksh file:
#!/bin/ksh
log_file="/logs/filename.long"
tail -f $log_file | awk '!(/list)'
Or even this which you would run with a command like ./test.ksh /logs/filename.log:
#!/bin/ksh
tail -f $1 | awk '!(/list)'
You wrote 2 different things.
In the shell, you stated that the output of tail -f is redirected to awk
In your script, you stated that tail -f should read data from the files named "/logs/filename.log", "|", "awk" and "!(/list)"
You want to write this in your script file:
#!/bin/ksh
variable="/logs/filename.log"
tail -f $variable | awk '!(/list)'
awkcode has syntax error.eval, but that's generally not advised.