Neither normal helium nor normal hydrogen can be used as fusion fuel, so the whole plot is impossible.
Fusion fuels are deuterium, tritium and helium-3 (ignoring proton-boron fusion).

Deuterium is easy to get by isotope separation from any natural occurring hydrogen source (water for example).
Tritium must be produced, either from lithium or from helium-3 (3He + n -> T + p!). Both methods use reaction with neutrons, tritium supply therefore depends on neutron supply. Tritium is also a by-product of deuterium-deuterium (D-D) fusion.
Helium-3 is difficult to get on Earth, but can be mined in the atmosphere of the gas giants (or on the Moon, but reserves are much more limited). Tritium decays into helium-3 with a half-life of 12 years. Like tritium helium-3 is a by-product of D-D fusion.
Note: you can produce both tritium from helium-3 and helium-3 from tritium, and both can be produced from deuterium if you have a D-D reactor.
Using pure helium-3 as fusion fuel (number 4 in the picture) is the cleanest option, because it does not produce neutrons, but it is also the one hardest to achieve. That would be the "rich man's fuel".
The reaction D-He3 is a bit easier to achieve and more energetic than pure He-3 fusion. But it is not as clean, because neutrons are produced by D-D side reactions.
The reaction D-T is the easiest to achieve, almost as energetic as D-He3 but also the dirtiest option, because it produces the most neutrons, so it would be the "poor man's option"
D-D is a special case. It is more difficult than D-T fusion and provides only a forth of the energy. However, it produces useful products: tritium and helium-3. Also, in a real life reactor, those products would react with the deuterium and also with each other (unless you separate them) resulting in energy output similar to D-T fusion.
In your plot the "poor man's fuel" is a waste product of the "rich man's fuel". That is not really the case and I can't see a reasonable way to save that part of the plot.