Print NULL fields from array using implode PHP?

Question

I have a strange problem. I have this piece of code:

$array = array('abc',null,'def',null);
$implode = implode(",", $array);
var_dump($implode);

and the result is:

string 'abc,,def,' (length=9)

Is there any way I can print null as a string? I mean, some thing like this:

string 'abc,null,def,null' (length=17)

Thanks a lot!

EDIT:

Thank you all for your responses. I think they are the same, but developed differently. I was thinking in array_map but I didn't know exactly how to use it. Thanks!

keune · Accepted Answer · 2015-04-30 21:47:10Z

6

You could use array_walk to go over every item in the array and turn them to string if they are null:

$array = array('abc',null,'def',null);
function x(&$el) {
    $el = ($el === null) ? 'null' : $el;
}
array_walk($array, 'x');
$implode = implode(",", $array);
var_dump($implode);

answered Apr 30, 2015 at 21:47

keune

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1 Comment

Yoluk Over a year ago

I was just about to post the same solution. Too fast 4 me ;)

Kevin · Accepted Answer · 2015-04-30 21:47:03Z

1

You could map the nulls before.

$arrayMapped = array_map(function ($val) { return $val != null ? $val : 'null';}, $array);

$implode = implode(",", $arrayMapped);

answered Apr 30, 2015 at 21:47

Kevin

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