Extracting substring from string in Python

Question

I have a string that looks like this:

catString = randomtextrandomtext (cats:1)=1 randomtext randomtextrandomtext (cats:3)=3 randomtext randomtext (cats:1540)=1,540 randomtextrandomtext randomtext (cats:85):85 randomtext

I want to print out a string that looks like this:

(cats:1)(cats:3)(cats:1540)(cats:85)

I tried doing:

catCount = ''

for a in catString:
    for b in line.split():
        if '(cats:' in b:
            catCount += str(part)
print catCount

However, that code prints out:

(cats:1)=1(cats:3)=3(cats:1540)=1,540(cats:85)=85

How can I achieve my desired result?

Tony Babarino · Accepted Answer · 2016-02-20 02:40:34Z

1

>>> ''.join(re.findall('\(cats:[0-9]+\)',catString)) 
'(cats:1)(cats:3)(cats:1540)(cats:85)'

answered Feb 20, 2016 at 2:40

Tony Babarino

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Comments

helloV · Accepted Answer · 2016-02-20 02:45:30Z

1

import re

''.join(re.findall(r'\(cats:\d*\)', catString))

edited Feb 20, 2016 at 2:45

answered Feb 20, 2016 at 2:37

helloV

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Comments

aghast · Accepted Answer · 2016-02-20 02:34:17Z

Use str.index and particularly the start parameter.

catString = "randomtextrandomtext (cats:1)=1 randomtext randomtextrandomtext (cats:3)=3 randomtext randomtext (cats:1540)=1,540 randomtextrandomtext randomtext (cats:85):85 randomtext"

result = ''
end = -1
try:
    while True:
        start = catString.index('(cats:', end+1)
        end = catString.index(')', start)
        result += catString[start:end+1]

except ValueError:
    pass

print(result)

Jyothi Babu Araja · Accepted Answer · 2016-02-20 02:32:04Z

0

Try this once

catCount = ''

for a in catString:
    for b in line.split():
        if '(cats:' in b:
            catCount += str(b[0,b.index(")")+1])
print catCount

answered Feb 20, 2016 at 2:32

Jyothi Babu Araja

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