How to convert the replace(%3A and %2F ...) in the url.
URL
https://url/login_data.php?username=user&categoryid=0&URL=https%3A%2F%2Furl%2F%26TIME%3DFri%2520Aug%252005%25202016%252011%3A40%3A14%2520GMT%2B0530%28India%2520Standard%2520Time%29
Required URL
https://url/login_data.php?username=user&categoryid=0&URL=https://url/&TIME=Sat Aug 06 2016 11:42:36 GMT+0530 (India Standard Time)
I was wondering is there any simple way to do this?
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3 Answers
In python 2.7, use urllib.unquote:
>>> import urllib
>>> urllib.unquote(urllib.unquote('https://url/login_data.php?username=user&categoryid=0&URL=https%3A%2F%2Furl%2F%26TIME%3DFri%2520Aug%252005%25202016%252011%3A40%3A14%2520GMT%2B0530%28India%2520Standard%2520Time%29'))
'https://url/login_data.php?username=user&categoryid=0&URL=https://url/&TIME=Fri Aug 05 2016 11:40:14 GMT+0530(India Standard Time)'
In python 3+, use urllib.parse.unquote
>>> from urllib.parse import unquote
>>> unquote(unquote("https://url/login_data.php?username=user&categoryid=0&URL=https%3A%2F%2Furl%2F%26TIME%3DFri%2520Aug%252005%25202016%252011%3A40%3A14%2520GMT%2B0530%28India%2520Standard%2520Time%29"))
'https://url/login_data.php?username=user&categoryid=0&URL=https://url/&TIME=Fri Aug 05 2016 11:40:14 GMT+0530(India Standard Time)'
Take a look at urllib.parse.unquote: "Replace %xx escapes by their single-character equivalent."
Comments
For python3,
import urllib.parse
urllib.parse.unquote_plus("https://url/login_data.php?username=user&categoryid=0&URL=https%3A%2F%2Furl%2F%26TIME%3DFri%2520Aug%252005%25202016%252011%3A40%3A14%2520GMT%2B0530%28India%2520Standard%2520Time%29")
