I have the following string in python:
text = "vagrant 11450 4344 0 Feb22 pts/2 00:00:28 python run.py abc"
I want to capture the text after time field that is "python run.py abc"
I am using the following regex but it is not working
[\d:]+ (.)*
You may use
\d+:\d+\s+(.*)
See the regex demo.
Details
\d+ - 1 or more digits: - a colon\d+ - 1 or more digits\s+ - 1 or more whitespace chars(.*) - Group 1 (the value you need to access using .group(1)): any 0+ chars other than line break chars, as many as possible (all the rest of the line).See the Python demo:
import re
text = "vagrant 11450 4344 0 Feb22 pts/2 00:00:28 python run.py abc"
m = re.search(r'\d+:\d+\s+(.*)', text)
if m:
print(m.group(1)) # => python run.py abc
With re.search() function:
import re
text = "vagrant 11450 4344 0 Feb22 pts/2 00:00:28 python run.py abc"
result = re.search(r'(?<=(\d{2}:){2}\d{2} ).*', text).group()
print(result)
The output:
python run.py abc
Without RE:
text = "vagrant 11450 4344 0 Feb22 pts/2 00:00:28 python run.py abc"
text=text.split(":")[-1][3:]
Output:
python run.py abc
You can use re.split and regex :\d{2}:\d{2}\s+.
text = 'vagrant 11450 4344 0 Feb22 pts/2 00:00:28 python run.py abc'
str = re.split(r':\d{2}:\d{2}\s+', text)[1]
Output: python run.py abc
r'\d+:\d+\s+(.*)'