Input:
'0x0 0x48 0x65 0x6c 0x6c 0x6f 0x8E 0x21'
Output:
Hello!
Current Solution:
s = []
birary_data = '0x0 0x48 0x65 0x6c 0x6c 0x6f 0x8E 0x21'.replace(' ', '').split('0x')
for c in birary_data:
if len(c) > 1:
s.append(bytes.fromhex(c).decode('utf-8', 'ignore'))
print("".join(s))
Need help with:
Could anyone suggest a more elegant solution, please?
Try this:
data = '0x0 0x48 0x65 0x6c 0x6c 0x6f 0x8E 0x21'
string = "".join([chr(int(item, 16)) for item in data.split()])
print(string)
Output:
Hello!
Another option is to remove 3 characters (or less) length substrings, 0x and white spaces. bytes.fromhex can handle a string like '48656c6c6f8E21'
binary_data = '0X0 0x48 0x65 0x6c 0x6c 0x6f 0x8E 0x21'
binary_data = re.sub(r'\b\w{3}\b|\s?0x', '', binary_data)
print(bytes.fromhex(binary_data).decode('utf-8', 'ignore'))
r'\b\w{3}\b|\s?0x' to get '48656c6c6f8E21' directly?You can use the below one Here in the code i am first splitting the hex according to white-space and then iterating and joining the character i get.
a = '0x0 0x48 0x65 0x6c 0x6c 0x6f 0x8E 0x21'
print(''.join(chr(int(i, 16)) for i in a.split()))
The builtin bytes.fromhex() is very nearly all we need. There are however two problems we need to get around:
0x8E)import re
data = '0x0 0x48 0x65 0x6c 0x6c 0x6f 0x8E 0x21'
string = bytes.fromhex(re.sub('0x(0 )?', '', data)).decode('utf-8', 'ignore')
The regex will take care of both stripping the null byte and formatting the string correctly for bytes.fromhex(). The ignore in the decode will skip the bad byte.
birary_data = '0x0 0x48 0x65 0x6c 0x6c 0x6f 0x8E 0x21'.replace('0x', '').split()
print(bytearray.fromhex(''.join(c for c in birary_data if len(c) > 1)).decode('utf-8', 'ignore'))
Output:
Hello!
