I've found this solution but it seems to be for Java SE. I can't find an alternative to the System.out.format() function. Also, I have changed the ByteBuffer.allocate() function to ByteBuffer.allocateDirect() is this correct?
byte[] bytes = ByteBuffer.allocate(4).putInt(1695609641).array();
for (byte b : bytes) {
System.out.format("0x%x ", b);
}
Thank you.
If you want network byte order aka big-endian order which is used throughout Java's serialization and remoting libraries:
static byte[] intToBytesBigEndian(int i) {
return new byte[] {
(byte) ((i >>> 24) & 0xff),
(byte) ((i >>> 16) & 0xff),
(byte) ((i >>> 8) & 0xff),
(byte) (i & 0xff),
};
}
// 32-bit integer = 4 bytes (8 bits each)
int i = 1695609641;
byte[] bytes = new byte[4];
// big-endian, store most significant byte in byte 0
byte[3] = (byte)(i & 0xff);
i >>= 8;
byte[2] = (byte)(i & 0xff);
i >>= 8;
byte[1] = (byte)(i & 0xff);
i >>= 8;
byte[0] = (byte)(i & 0xff);
