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2 votes
0 answers
82 views

Summary of the question: I wanted to know if there is a "simple" topological argument to prove that the inclusion $\operatorname{PGL}_n \rightarrow \operatorname{GL}_{n^2}$ is a topological ...
bru's user avatar
  • 21
4 votes
0 answers
81 views

There is a claim on Baker's Matrix Groups about inner automorphisms which states the following: Proposition 4.49: Let $A$ be a finite dimensional (normed) algebra over $\mathbb{R}$. Then the inner ...
Kamineko's user avatar
  • 353
4 votes
1 answer
313 views

Matrices have two obvious and basic antihomomorphisms (maps satsisfying $\phi(AB)=\phi(B)\phi(A)$): Transposition: $(AB)^T=B^TA^T$ Inversion: $(AB)^{-1}=B^{-1}A^{-1}$ (where here we consider only ...
FamisherCaterpillar's user avatar
4 votes
2 answers
140 views

Does anyone know any good references on the structure of/general facts about $GL_n(\mathbb{F}_q)$ which is to say the general linear group over a finite field of order q (with $q=p^k$ for p a prime)? ...
FamisherCaterpillar's user avatar
0 votes
0 answers
52 views

Let $\mathbb{Z}_{p}$ be the ring of $p$-adic integers and let ${\rm SL}_{2}(\mathbb{Z}_{p})$ be the two dimensional special linear group over $\mathbb{Z}_{p}$. Note that ${\rm SL}_{2}(\mathbb{Z}_{p})$ ...
stupid boy's user avatar
1 vote
1 answer
119 views

I'm currently working on an applied problem that boils down to knowing about the representation theory of the affine group $Aff(\mathbb{R}^n)\cong \mathbb{R}^n\rtimes GL(n,\mathbb{R})$. I am ...
Kiah's user avatar
  • 312
0 votes
0 answers
48 views

Let $F$ be a finite field and let $G$ be the subgroup of upper triangular matrices in $GL_n(F)$. I am working through an exercise to show that $G$ is a soluble group. The exercise has the following ...
Elliptic2005's user avatar
0 votes
1 answer
86 views

I am working out of Artin's Algebra. I was wondering what he meant by "we haven't run across the longitude $cI + s\mathbf{k}$ before." There doesn't seem to be any further mention of this ...
Ray's user avatar
  • 45
0 votes
1 answer
76 views

Let $k$ be an algebraically closed field and $G:= \operatorname {Sp}(2n,k)$ the symplectic group. It is not that difficult to show, that it is in fact a linear algebraic group in both: $k^{n^2+1}$ and ...
Tina's user avatar
  • 1,390
0 votes
1 answer
102 views

The center of $SL_2(\mathbb{F}_3)$ and $GL_2(\mathbb{F}_3)$ are both $\{I,-I\}$. In the upper central series of $G=GL_2(\mathbb{F}_3)$, we thus have $Z_1=Z(G)=\{I,-I\}$. $Z_2$ is defined by the ...
Shean's user avatar
  • 1,022
5 votes
2 answers
168 views

In chapter 14 of Galois Theory by David Cox the author classifies (or at the very least describes in a pretty satisfying way) all possible solvable Galois groups of irreducible polynomials over $\...
roymend's user avatar
  • 553
0 votes
1 answer
118 views

Let $G = GL_n(\mathbb{C})$. A rational representation of $G$ is a group homomorphism $\varphi: G \to GL(V)$, where $V$ is a finite-dimensional vector space over $\mathbb{C}$, and $\varphi$ is given by ...
user avatar
0 votes
1 answer
73 views

I'm studying the adjoint representation of $GL_n(\mathbb{C})$, and I'm encountering some confusion about the denominator that appears in the matrix entries of the adjoint action. The adjoint ...
user avatar
1 vote
0 answers
55 views

The examples I know of non-unimodular (locally compact second countable) groups arise as subgroups the general linear group (e.g. the affine linear group). I was wondering whether there is an example ...
Uri George Peterzil's user avatar
0 votes
0 answers
102 views

In this answer to a question from a while back, it says that the Valentiner group is isomorphic to $PGL_3(\mathbb{F}_4)$. However, when I implement in sage: ...
FamisherCaterpillar's user avatar

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