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Questions tagged [spectral-radius]

The spectral radius of a square matrix or a bounded linear operator is the largest absolute value of its spectrum.

2 votes
0 answers
38 views

Let $A \in \mathbb{R}^{m, n}$, with $n > m$ and $\text{rank}(A) = m$, and let $\mathcal{B}$ be the set of square $m\times m$ submatrices of $A$. In other words, $\mathcal{B}$ contains all matrices $...
Tend's user avatar
  • 21
1 vote
1 answer
89 views

I have a matrix $A$ that is a quadratic function of a real scalar $\beta$ and real constant matrices $B,C,D$: $$ A = B + \beta C + \beta^2 D $$ I want to find the value of $\beta$ that minimises the ...
Jake Levi's user avatar
  • 255
1 vote
0 answers
90 views

For the sake of concreteness, I will be working on the Hilbert space $H=L^2([0,1])$. Let $T$ be a bounded compact operator on $H$ given by a kernel $K\in L^2([0,1]^2)$. In my application, $K$ is non-...
Jan Hladky's user avatar
4 votes
1 answer
122 views

Let $M$ be the block matrix $$M = \begin{bmatrix} A & B \\ C & D \end{bmatrix}, $$ where $A,B,C,D$ are all real, square, and symmetric positive semidefinite. Is it true that the spectral ...
user2625389's user avatar
2 votes
3 answers
286 views

I have the follow problem from a Chinese functional analysis book. I try to use English to describe it. If there are any mistakes or places that are unclear, please tell me and I will correct. Let $X$ ...
Enhao Lan's user avatar
  • 6,956
-1 votes
1 answer
66 views

I'm looking for an example of a real square matrix $A \in \mathbb{R}^{n \times n}$ with non-negative entries that satisfies all of the following conditions: There exists an eigenvalue $\lambda \ne \...
Tom's user avatar
  • 1
1 vote
1 answer
120 views

Let $X$ be a Banach space. Denote $$ L(X) = \{T:X\rightarrow X \mid T \text{ is linear and bounded} \}. \tag{1} $$ Then, for any $A\in L(X)$, why $$ |\lambda| > \limsup_{n\to\infty} {\|A^n\|}^{\...
Enhao Lan's user avatar
  • 6,956
2 votes
1 answer
129 views

Recently, I’ve been studying the Katz centrality index on sparse graphs, and now I’m shifting toward very dense graphs, following Noferini & Wood$^\color{magenta}{\star}\!$. However, a thought ...
user avatar
3 votes
0 answers
128 views

Let $k, a, b > 0$ and $b < 1$. Define the $n \times n$ Hessenberg Toeplitz matrix $$ {\bf A}_n := \begin{bmatrix} ab & ab^2 & ab^3 & \cdots & ab^n \\ ...
Hots123's user avatar
  • 67
1 vote
0 answers
56 views

Question: is the following proof correct? Let $X \in \mathbb{R}^{n \times n}$ be a diagonalizable matrix, i.e., $X=V D V^{-1}$ for some invertible matrix $V$ and diagonal matrix $D$. Let $\rho(X)=\max ...
redS's user avatar
  • 11
0 votes
0 answers
49 views

Prove that the Jacobi method converges for every $2 \times 2$ system given by a symetrical definite positive matrix. I tried building the iteration matrix $B_J = -D^{-1} (L+U)$ given a matrix $$ A= \...
lmendezayala's user avatar
0 votes
0 answers
90 views

Mostly what the title says. We have further that $A$ is positive definite and $B$ is positive semi definite. Assuming that $A\geq B$, I am able to conclude that: $$x^*(I-BA^{-1})x = x^*(A-B)A^{-1}x \...
StuckInTheFridge's user avatar
1 vote
0 answers
76 views

Given a Matrix $A$ with spectral radius $\rho(A)$, we can prove that $\rho(A+I)\leq\rho(A)+1$. This is the case, since the spectral radius is defined as $\rho(A)=\max{|\lambda_i|}$ and the eigenvalues ...
H2O2's user avatar
  • 21
0 votes
1 answer
42 views

If $A$ is a complex matrix, and $\rho(A)$ is its spectral Radius, then Jairo Bochi's answer to this question, $$\left\|A^d\right\|\leq C\rho(A)\left\|A\right\|^{d-1};\quad (Eq.\, I)$$ where $C>0$. ...
Gomes93's user avatar
  • 2,359
3 votes
1 answer
51 views

For a complex, Hermitian, positive semi-definite matrix $ X \in \mathbb{C}^{2d \times 2d}$ of the form $$ X = \begin{bmatrix} A & B \\ B & C \end{bmatrix} \, ,$$ such that $A, B, C \in \mathbb{...
Aritra Das's user avatar
  • 3,652

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