array_push not working in foreach loop [closed]

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print_r($members) coming like this following result

Array ( [myname] => Array ( [userid] => 52 [age] => 46 )
Array ( [hisname] => Array ( [userid] => 22 [age] => 47 )
Array ( [yourname] => Array ( [userid] => 47 [age] => 85 )

array_push() push not working in the foreach loop

foreach($members as $key => $item){
  // print "<br>" . $key ."<br>";
  array_push($members, '$key');
}

The result expecting like this following code with the array_push()

Array ( [myname] => Array ( [userid] => 52 [age] => 46 [0] => myname)
Array ( [hisname] => Array ( [userid] => 22 [age] => 47 [0] => hisname)
Array ( [yourname] => Array ( [userid] => 47 [age] => 85 [0] => yourname)

result

Warning: array_push() expects parameter 1 to be array, null given in C:\xampp\htdocs\index.php on line 126

And what is the output result? Ans what is $arr in your foreach? — Gwenc37
– Gwenc37, Commented May 22, 2014 at 9:59
That warning comes because you do not initialize $arr as an (empty) array. Place this before the loop: $arr=[];. No idea why that happens in all iterations though... — arkascha
– arkascha, Commented May 22, 2014 at 10:04
Oh, and: '$key' pushes the literal string "$key" onto the array, not the content of that variable. — arkascha
– arkascha, Commented May 22, 2014 at 10:06
Now you've changed the code in the question, and it seems that you are pushing data into $members, the same array which you are iterating. That seems like a bad idea. — GolezTrol
– GolezTrol, Commented May 22, 2014 at 10:10
@GolezTrol yes that is what I need to see in the end result. Create new array which should be the key. Hope you understand the question — Mo.
– Mo., Commented May 22, 2014 at 10:13

Rikesh · Accepted Answer · 2014-05-22 10:00:23Z

5

Because $arr does not seems to be an array. Change your code to,

foreach($members as $key => $item){
   array_push($members[$key], $key); //or $members[$key][] = $key;
}

answered May 22, 2014 at 10:00

Rikesh

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