Echo PHP array with index numbers

Question

array(13) {
    [0]=> string(15) "TEST1"
    [1]=> string(12) "TEST2"
    [2]=> string(12) "TEST3"
    [3]=> string(12) "TEST4"
}

Output should look like this:

0 TEST1
1 TEST2
2 TEST3
...

I'm new to arrays so I'm searching for the cleanest way to do it. It worked with some counter variables but it was ugly as hell. Thanks for your time.

Take a look at foreach, I'm sure you will get to your solution. — Rizier123
– Rizier123, Commented Jan 3, 2016 at 20:39
@devpro, how would you use a for loop? I can only think it's useful for known integer-indexed arrays starting at 0, with sequential keys. — Progrock
– Progrock, Commented Jan 3, 2016 at 21:58

user4962466 · Accepted Answer · 2016-01-03 20:41:16Z

3

You can use a foreach loop

foreach($array as $key => $value) {
    echo $key . " " . $value . "\n";
}

answered Jan 3, 2016 at 20:41

user4962466

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4 Comments

Jonas Knobloch Over a year ago

Exactly what I was looking for. Didn't know that ($array as $key => $value) is possible. Thanks!

devpro Over a year ago

This is the most easy way love this.. u can also use for loop for it @jonas-knobloch

crafter Over a year ago

@JonasKnobloch, don't take this the wrong way, but if you didn't know this, you obviously didn't look up the PHP reference, which is the defactor reference to the language. You should spend some time here : php.net/docs.php ( and php.net/manual/en/language.types.array.php )

Jonas Knobloch Over a year ago

Yeah. I'm new to PHP and should spend more time with the documentation. My question looks now more dumb every day for me. Have a nice day.

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