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Questions tagged [improper-integrals]

Questions involving improper integrals, defined as the limit of a definite integral as an endpoint of the interval of integration approaches either a specified real number or $\infty$ or $-\infty$, or as both endpoints approach limits.

0 votes
0 answers
75 views

I am studying the definite integral $$ I = \int_{0}^{1} \frac{\ln(1+x)}{\ln(1-x)}\,dx . $$ The integral does converge: as $x \to 0$, $\ln(1+x) \sim x$ and $\ln(1-x) \sim -x$, so the ratio tends to $-...
Jamal Hanus Jr's user avatar
40 votes
7 answers
2k views

Problem: You are standing at the origin of an infinite flat earth. One quadrant of the earth is gone, leaving an infinite abyss. You have an infinite supply of unit-length zero-width planks. How far ...
The Guy with The Hat's user avatar
4 votes
1 answer
217 views

There are evaluations of the above integral using complex analytic techniques, but is there a real variables way to show it? I've tried the "Feynman differentiation under the integral trick" ...
Julie's user avatar
  • 140
6 votes
4 answers
376 views

The integral converges since $|a|<1$. In the special case of $a=0$, the integral $$I(a)=\int_0^\infty \frac{\ln(1+x^2)}{x^2+2a x+1}dx $$ is well-known, which is $$\int_0^\infty \frac{\ln(1+x^2)}{1+...
Ace's user avatar
  • 2,958
6 votes
6 answers
367 views

The integral $$ \int_0^{\infty} \frac{\ln \left(x+\frac{1}{x}\right)}{1+x^2}=\pi \ln 2 $$ invites me to investigate the integral $$ I=\int_0^{\infty} \frac{\ln \left(x+\frac{1}{x}\right)}{x^4+1} d x $$...
Lai's user avatar
  • 33.2k
5 votes
2 answers
277 views

Being attracted by the answer in the post $$\int_0^{\infty} \frac{\sin (\tan x) }{x} d x = \frac{\pi}{2}\left(1- \frac 1e \right) , $$ I started to investigate and surprisingly found that $$ \int_0^{\...
Lai's user avatar
  • 33.2k
5 votes
4 answers
243 views

Latest news Thanks a lot for the contributions from both @Luce with @FDP and @ Sangchul Lee who brought us a very decent alternative methods(checked by the Desmo) for the general integral: $$\boxed{\...
Lai's user avatar
  • 33.2k
1 vote
0 answers
64 views

I'm trying to determine the values of $n$ for which the following integral converges: $$\int_0^1 \frac{x^n \log x}{(1+x)^2} \, dx$$ The only point of discontinuity is at $x = 0$. My attempt: I used ...
dreamboat's user avatar
9 votes
3 answers
447 views

Being attracted by the result $$\int_0^{\infty} \frac{\tan ^{-1}\left(\tan ^2 x\right)}{x^2}\,dx=\frac{\pi}{\sqrt 2}, $$ I tried to generalise the integral for any even integer $n\ge 2$, $$I_n=\int_0^{...
Lai's user avatar
  • 33.2k
15 votes
4 answers
696 views

I recently constructed the following integral for natural numbers $n$, which led me to an interesting discovery. $$I_n = \int_0^{\pi} \frac{x \sin(nx)}{1 - \cos x}dx $$ Using online tools, I obtained ...
Rishit Garg's user avatar
  • 1,124
4 votes
0 answers
266 views

When I was on Twitter, I saw the integral $$\int_{1}^{\infty}\frac{\ln\left(\arctan\left(x\right)\right)}{x^{2}+\ln\left(x^{2}+1\right)}\,\mathrm dx.$$ The solution was not part of the post, but I ...
rain's user avatar
  • 181
1 vote
1 answer
51 views

I was trying to get a better feeling for the Stieljes transform by applying it to the Lebesgue measure restricted to $[0,1]$ but I am having an issue to finish the computation. For a Borel probability ...
Keen-ameteur's user avatar
  • 8,566
3 votes
1 answer
141 views

Does the integral $$\int_{0}^{\infty}(\sin\left(1-e^{-x}\right)-\sin\left(1\right))dx$$ converge? If so, how would I solve it? It seems to be a $\infty-\infty$ indeterminate limit but I have been ...
rain's user avatar
  • 181
8 votes
1 answer
272 views

Recently I was learning to evaluate the improper integral $$ I=\int_{-\infty}^\infty\frac{du}{u^2+2} $$ My instructor said that we could write $$ I=\lim_{t\to\infty}\int_{-t}^t \frac{du}{u^2+2}=\lim_{...
Tseng's user avatar
  • 143
0 votes
1 answer
133 views

I have a question regarding the formula $$\int_{0}^{\infty}\int_{0}^{\infty}\sin(xy)xf(x)\,\mathrm dx\,\mathrm dy=\int_{0}^{\infty}f(x)\,\mathrm dx.$$ I derived it this by moving integrals inside each ...
d ds's user avatar
  • 1,376

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