One of my daydreams is a non rotating sky hook anchored on Phobos.
I was wondering how to calculate the Coriolis Force induced by ascending or descending elevator cars.
Wikipedia tells me:
Coriolis Force = -2m(ω X v')
It seems to me traveling straight up (or down) that v' would be perpendicular to ω, correct? So to get magnitude of this cross product I could use straight multiplication?
So let's say I have a 5 tonne elevator car doing straight up the tether at 200 meters/second. Phobos has a period of about 7.66 hours.
ω = .00023 rads/sec.
v' = 200 meters/sec straight up.
mass elevator car = 5000 kg
5000 kg * 200 m/s * .00023/sec = 460 newtons
So in this scenario I get a 460 newton push sideways.
Did I do that correctly?
