How to parse string with regex in Java?

Question

How can I parse such data with Java regex?

data.param[0] 
0 - is any non negavite digit

Here is my try -

String result = Pattern.compile("(data.param[)(\\d+)(])").matcher("data.param[13123]").group();

What is the output you are expecting? The digit in between the square brackets? The param[digit] idiom? Note that your . should be double-escaped in the Pattern. — Mena
– Mena, Commented Sep 16, 2014 at 16:15

anubhava · Accepted Answer · 2014-09-16 16:15:09Z

5

You can use this regex:

Pattern p = Pattern.compile("data\\.param\\[(\\d+)\\]");
Matcher m = p.matcher("data.param[13123]");

if (m.find())
    System.out.println(m.group(1));

answered Sep 16, 2014 at 16:15

anubhava

790k67 gold badges603 silver badges671 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Alex Over a year ago

Yes. It's fine solution. Thanks. Will accept it in a 9 mins.

Collectives™ on Stack Overflow

How to parse string with regex in Java?

1 Answer 1

1 Comment

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Linked

Related