I have a bunch of files named like this:
File one - some name - 01-05-2020
File two - some name - 01-07-2020
File three - some name - 01-15-2020
What I need is to replace:
My expected result would be:
File-one_some-name_01-05-2020
File-two_some-name_01-07-2020
File-three_some-name_01-15-2020
PD: I'm using Manjaro which is Arch based.
One solution with mvand sed:
for file in *; do echo mv "$file" "$(echo $file | sed 's/ - /_/g ; s/ /-/g')" ; done
Remove first echo to commit changes.
Tests
$ for file in *; do echo mv "$file" "$(echo $file | sed 's/ - /_/g ; s/ /-/g')" ; done
mv File one - some name - 01-05-2020 File-one_some-name_01-05-2020
mv File three - some name - 01-15-2020 File-three_some-name_01-15-2020
mv File two - some name - 01-07-2020 File-two_some-name_01-07-2020
for file in *; do echo mv \"$file\" "$(echo $file | sed 's/ - /_/g ; s/ /-/g')" ; done
Using Larry Wall's "perl rename" (rename on Debian/Ubuntu, prename on RHEL/Centos/Fedora):
rename -n -E 's/ - /_/g' -E 's/ /-/g' {file[s]}
Remove -n (or replace by -v) for actual execution.
rename: invalid option -- 'E', I forget to specify my distro, I'm using Manjaro which is Arch based, maybe it has something to do with this?
rename. man rename should mention Larry Wall in the AUTHOR section at the end. On ArchLinux (and therefore Manjaro) Manjaro it seems to be in the perl-rename package.
--help there is no -E.
rename -V says /usr/bin/rename using File::Rename version 0.20. It takes both -e and -E, the difference being that -E adds a ; at the end and as far as I can tell this is required if you have more than one command.