how to return boolean value based on condition check in array object javascript

Question

I have object array obj1, obj2,

if the name of object cannot have All key name return true

if the name of object can have only one All key name and other object return false

if the name of object can have only one All key name and no other object return true

if the name of object has too many key name All return false

based on above conditions how to do in javascript.

function checkObj(ob){
  var result = ob.filter(e=>e.name=="All");
  if(result.length !== 1){
    return false;
  }
  else{
    return true;
  }
}

var  obj1=[
  {id:1, name: "All", value:"all"},
  {id:2, name: "Sun", value:"sun"},
  {id:3, name: "Mon", value:"mon"},
]

var  obj2=[
  {id:4, name: "Thur", value:"thur"},
  {id:8, name: "Mon", value:"mon"},
]

var  obj3=[
  {id:1, name: "Thur", value:"thur"},
  {id:5, name: "All", value:"all"},
  {id:2, name: "Mon", value:"mon"},
  {id:6, name: "All", value:"all"}
]

var obj4=[
{id:1, name: "All", value:"all"}
]

var r1= this.checkObj(obj1);
var r2=this.checkObj(obj2);
var r3=this.checkObj(obj3);
var r4=this.checkObj(obj4);

Expected Output:

false
true
false
true

also, I would use .some() for this case developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… — Muhammad Usman
– Muhammad Usman, Commented Oct 19, 2020 at 7:20
@MuhammadUsman I didn't see your comment before posting my answer — Cid
– Cid, Commented Oct 19, 2020 at 7:35

adiga · Accepted Answer · 2020-10-19 08:01:37Z

2

You can check if the array has any objects with name = "All".

Then, return true if

The array has name = "All" object and the array's length is 1
or the array doesn't have name = "All"

function checkObj(arr) {
  const hasAll = arr.some(o => o.name === "All")
  return (arr.length === 1 && hasAll) || !hasAll
}

Here's a snippet:

function checkObj(arr) {
  const hasAll = arr.some(o => o.name === "All")
  return (arr.length === 1 && hasAll) || !hasAll
}

const obj1=[{id:1,name:"All",value:"all"},{id:2,name:"Sun",value:"sun"},{id:3,name:"Mon",value:"mon"},],
    obj2=[{id:4,name:"Thur",value:"thur"},{id:8,name:"Mon",value:"mon"},],
    obj3=[{id:1,name:"Thur",value:"thur"},{id:5,name:"All",value:"all"},{id:2,name:"Mon",value:"mon"},{id:6,name:"All",value:"all"}],
    obj4=[{id:1,name:"All",value:"all"}];

console.log( checkObj(obj1) )
console.log( checkObj(obj2) )
console.log( checkObj(obj3) )
console.log( checkObj(obj4) )

edited Oct 19, 2020 at 8:01

answered Oct 19, 2020 at 7:23

adiga

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3 Comments

codecat Over a year ago

if only one All present and has other objects return false, how to check this, thanks

adiga Over a year ago

@codecat What is the difference between point 2 and 3 in your question? "if the name of object can have only one All key name and other object return false. if the name of object can have only one All key name and no other object return true". I did not understand the difference

codecat Over a year ago

thansk for reply, have added the obj4 example for "if the name of object can have only one All key name and no other object return true" obj1 example for ". if the name of object can have only one All key name and no other object return true"

Nina Scholz · Accepted Answer · 2020-10-19 07:41:03Z

2

You could take Array#every with a short circuit on counts over one.

function checkArray(array) {
    return array.every((count => ({ name }) => (count += name === "All") < 2)(0));
}

var array1 = [{ id: 1, name: "All", value: "all" }, {  id: 2, name: "Sun", value: "sun" }, { id: 3, name: "Mon", value: "mon" }],
    array2 = [{ id: 4, name: "Thur", value: "thur" }, { id: 8,  name: "Mon", value: "mon" }],
    array3 = [{ id: 1, name: "Thur", value: "thur" }, { id: 5, name: "All",  value: "all" }, { id: 2, name: "Mon",  value: "mon" }, { id: 6, name: "All", value: "all" }];

console.log(checkArray(array1), checkArray(array2), checkArray(array3));

edited Oct 19, 2020 at 7:41

answered Oct 19, 2020 at 7:35

Nina Scholz

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2 Comments

codecat Over a year ago

if only one All present and has other objects return false, how to check this, thanks

Nina Scholz Over a year ago

coun need the count variable outside of the function: let count = 0; array.every(({ name }) => (count += name === "All") < 2); return count === 1;

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